【easy】235. Lowest Common Ancestor of a Binary Search Tree

题意大概是,找两个节点的最低公共祖先

/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* lowestCommonAncestor(TreeNode* root, TreeNode* p, TreeNode* q) {
if (root == NULL)
return NULL;
if (root->val > p->val && root->val > q->val)
return lowestCommonAncestor(root->left,p,q);
if (root->val < p->val && root->val < q->val)
return lowestCommonAncestor(root->right,p,q);
return root; //出现了一大一小,就可以返回root了
}
};
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