C++算法题:一个3位数的平方是6位数,输出这9个数字各不相同的所有三位数

#include<iostream>
#include<vector>
using namespace std;

bool  isNumber(vector<int> v1, vector<int> v2) {
	for (int i = 0; i < v1.size(); i++) {
		for (int j = 0; j < v2.size(); j++) {
			if (v1[i] == v2[j]) return false;
		}
	}
	return true;
}
bool isSingle(vector<int>v) {
	for (int i = 1; i < v.size(); i++) {
		for (int j = 0; j < i; j++) {
			if (v[i] == v[j]) return false;
		}

	}
	return true;
}




int main() {
	
	for (int i = 100; i <= 999; i++) {
		vector<int> v1, v2;
		int k = i * i;
		int y = i;
		while (k != 0)
		{
			int j = k % 10;
			v1.push_back(j);
			k /= 10;
		}
		while (y != 0)
		{
			int u = y % 10;
			v2.push_back(u);
			y /= 10;
		}

		if (isNumber(v1, v2) && isSingle(v1) && isSingle(v2)) {
			cout << i << " ";
		}
	}
}

输出结果为:209,259,567,807,854

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