1.基本需求
编写登陆接口,实现如下需求:
(1)输入用户名密码
(2)认证成功后显示欢迎信息
(3)输错三次后锁定
2.实现细节
·每添加一个用户,需要手动添加三个文件
文件 | 功能 |
username_count.txt | 记录用户输错密码的次数,最大为3次,如果用户密码输入正确,则重置为0,默认为0 |
username_lock.txt | 记录用户是否被锁定,1表示锁定,0表示未锁定,默认为0 |
username_passwd.txt | 记录用户的密码 |
·注:username是指该用户的用户名,视具体的用户名而定;
·每添加一个用户,在username.txt中写入该用户名,一个用户名占一行(手动);
·如果输入的用户名或密码为空,都要求重新输入;
·输入不存在的用户名,只会提示“username or password wrong”;
·输入存在的用户名,才会进行密码输入错误次数的记录。
3.实现代码与注释
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import sys,os
count = 0 #To count, if the user is locked.
mark_user = 0 #To make sure if the user is existing.
mark_passwd = 0 #To make sure if the password is right.
while count < 3 :
name = raw_input( 'Username:' ).strip()
if len(name) == 0 :
print 'The username can not be empty!'
continue
key = raw_input( 'Password:' ).strip()
if len(key) == 0 :
print 'The password can not be empty!Try again!'
continue
#Upon:To check if the username or password is empty.检查用户名或密码是否为空
f = file( 'username.txt' , 'r' )
userlist = f.readlines()
f.close()
for user in userlist:
if user.strip() == name:
mark_user = 1
#检查输入的用户是否在username.txt文件中,即是否注册,如果在,mark_user = 1
if mark_user == 1 :
f = file( '%s_lock.txt' % (name), 'r' )
locked = int (f.readline().strip())
f.close()
else :
print 'Username or password wrong!' break
#Upon:To check if exist, if not exist,printing username or password wrong!And quit the program.
#用户名不存在就提示用户名或密码错误,用户名存在就检查该用户是否被锁定 if locked == 1 :
sys.exit( 'Sorry, the username had been locked!!!Please call the system administrator.' )
#Upon:To check if the username is locked by the system.
else :
f = file( '%s_passwd.txt' % (name), 'r' )
passwd = (f.readline().strip())
if passwd.strip() == key:
mark_passwd = 1
# check the password from the name_input password file.
if mark_user == 1 and mark_passwd == 1 :
f = file( '%s_count.txt' % name, 'w' )
f.write( '0' )
f.close()
sys.exit( '%s, welcome to our system!' % name)
#用户名和密码正确,将username_count.txt内容重置为 0 else :
f = file( '%s_count.txt' % name, 'r' )
count = int ((f.read().strip()))
f.close()
count += 1
f = file( '%s_count.txt' % name, 'w' )
f.write(str(count))
f.close()
#open the count file of the user and change it. #密码不正确,就把count次数记录在该用户名对应的文件count文件上 print '' 'Username or password wrong!
And the username '%s' has %d more chances to retry! '' ' % (name, 3 - count)
if count == 3 :
print "'%s' has been locked!!!" % (name)
if os.path.exists( '%s_lock.txt' % (name)):
fobj = open( '%s_lock.txt' % (name), 'w' )
fobj.writelines( '1\n' )
else :
print 'Username or password wrong!'
continue
#Upon:To check if the username and password are right, if not, the count will add 1 .
#如果count次数为 3 ,则将用户对应的lock文件内容重置为 1 ,锁定该用户
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4.测试
--对单一用户xpleaf的测试
·在对应4个文件中添加相应信息:
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xpleaf@xpleaf-machine:~/seminar6/day1$ head username.txt xpleaf_count.txt xpleaf_lock.txt xpleaf_passwd.txt ==> username.txt <== xpleaf ==> xpleaf_count.txt <== 0 ==> xpleaf_lock.txt <== 0 ==> xpleaf_passwd.txt <== xpleaf123 |
·正常输入用户名和密码:
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xpleaf@xpleaf-machine:~/seminar6/day1$ python newlogin.py Username:xpleaf Password:xpleaf123 xpleaf, welcome to our system! |
·故意输错两次密码后查看相关文件:
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xpleaf@xpleaf-machine:~/seminar6/day1$ python newlogin.py Username:xpleaf Password:klkdf Username or password wrong! And the username 'xpleaf' has 2 more chances to retry!
Username:xpleaf Password:kldf Username or password wrong! And the username 'xpleaf' has 1 more chances to retry!
Username:Traceback (most recent call last): File "newlogin.py" , line 8 , in <module>
name = raw_input( 'Username:' ).strip()
EOFError xpleaf@xpleaf-machine:~/seminar6/day1$ cat xpleaf_count.txt 2 |
·可以看到count文件已经记录为2,再输入正确的用户名和密码:
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xpleaf@xpleaf-machine:~/seminar6/day1$ python newlogin.py Username:xpleaf Password:xpleaf123 xpleaf, welcome to our system! xpleaf@xpleaf-machine:~/seminar6/day1$ cat xpleaf_count.txt 0 |
·count文件重置为0;
·连续输入密码错误超过3次:
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0xpleaf@xpleaf-machine:~/seminar6/day1$ python newlogin.py Username:xpleaf Password:kldf Username or password wrong! And the username 'xpleaf' has 2 more chances to retry!
Username:xpleaf Password:klkdf Username or password wrong! And the username 'xpleaf' has 1 more chances to retry!
Username:xpleaf Password:kldf Username or password wrong! And the username 'xpleaf' has 0 more chances to retry!
'xpleaf' has been locked!!!
xpleaf@xpleaf-machine:~/seminar6/day1$ python newlogin.py Username:xpleaf Password:xpleaf123 Sorry, the username had been locked!!!Please call the system administrator. xpleaf@xpleaf-machine:~/seminar6/day1$ cat xpleaf_lock.txt 1 |
·用户已经被锁定,对应lock文件内容变为1,如果需要解锁,则要手动将该文件重置为0;
·输入错误的用户名:
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xpleaf@xpleaf-machine:~/seminar6/day1$ python newlogin.py Username:klkdlf Password:klkdf Username or password wrong! |
·只会提示用户名或密码错误,不会做相关文件记录;
--对两个用户xpleaf和yonghaoyip的测试
·为用户yonghaoyip添加相关文件信息:
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xpleaf@xpleaf-machine:~/seminar6/day1$ head username.txt yonghaoyip_count.txt yonghaoyip_lock.txt yonghaoyip_passwd.txt ==> username.txt <== xpleaf yonghaoyip ==> yonghaoyip_count.txt <== 0 ==> yonghaoyip_lock.txt <== 0 ==> yonghaoyip_passwd.txt <== yonghaoyip123 |
·主要测试两个用户的count文件记录:
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对用户yonghaoyip操作: xpleaf@xpleaf-machine:~/seminar6/day1$ python newlogin.py Username:yonghaoyip Password:klkdf Username or password wrong! And the username 'yonghaoyip' has 2 more chances to retry!
Username:yonghaoyip Password:kldf Username or password wrong! And the username 'yonghaoyip' has 1 more chances to retry!
Username:Traceback (most recent call last): File "newlogin.py" , line 8 , in <module>
name = raw_input( 'Username:' ).strip()
EOFError 对用户xpleaf操作: xpleaf@xpleaf-machine:~/seminar6/day1$ python newlogin.py Username:xpleaf Password:kkjlkdf Username or password wrong! And the username 'xpleaf' has 2 more chances to retry!
Username:xpleaf Password:xpleaf123 xpleaf, welcome to our system! 查看两个用户对应的count文件记录: xpleaf@xpleaf-machine:~/seminar6/day1$ head yonghaoyip_count.txt xpleaf_count.txt ==> yonghaoyip_count.txt <== 2 ==> xpleaf_count.txt <== 0 |
·可以看到两个用户的相关文件并不会相互影响。