这个问题已经在这里有了答案：            >            Javascript – sort array based on another array                                    18个
我有一个看起来像这样的数组：

order = [ "foo", "bar", "baz" ];

该数组包含我要对对象数组进行排序的属性值.我想对数据进行排序,以使所有名称为“ foo”的对象首先出现,然后是“ bar”,然后是“ baz”.我的对象数组看起来像这样：

data = [ 
    {name: "foo", score: 8},
    {name: "baz", score: 4},
    {name: "baz", score: 9}, 
    {name: "foo", score: 6}, 
    {name: "bar", score: 9} 
];

我想要数据顺序的结果看起来像这样,当名称相同时,数组按名称排序,也按score desc排序：

sortedData =  [ 
    {name: "foo", score: 8},
    {name: "foo", score: 6},  
    {name: "bar", score: 9},
    {name: "baz", score: 9},
    {name: "baz", score: 4} 
];

这是到目前为止我尝试过的代码：

order.forEach(name => {
      sortedData = [...this.data].sort(function(obj1, obj2) {
            return (
              -(obj1.name)  || obj2.score < obj1.score
            );
          });
        });
console.log(sortedData);

解决方法:

您可以简单地使用sort和indexOf

let order = [ "foo", "bar", "baz" ];

let data = [ 
    {name: "foo", score: 8},
    {name: "baz", score: 4},
    {name: "baz", score: 9}, 
    {name: "foo", score: 6}, 
    {name: "bar", score: 9} 
];

let op = data.sort((a,b)=> (order.indexOf(a.name) - order.indexOf(b.name)) || b.score - a.score )

console.log(op)