A matrix is Toeplitz if every diagonal from top-left to bottom-right has the same element.

Now given an M x N matrix, return True if and only if the matrix is Toeplitz.

Example 1:

Input: matrix = [[1,2,3,4],[5,1,2,3],[9,5,1,2]]
Output: True
Explanation:

1234

5123

9512

In the above grid, the diagonals are "[9]", "[5, 5]", "[1, 1, 1]", "[2, 2, 2]", "[3, 3]", "[4]", and in each diagonal all elements are the same, so the answer is True.

Example 2:

Input: matrix = [[1,2],[2,2]]
Output: False
Explanation:

The diagonal "[1, 2]" has different elements.

Note:

1. matrix will be a 2D array of integers.
2. matrix will have a number of rows and columns in range [1, 20].
3. matrix[i][j] will be integers in range [0, 99].

class Solution(object):

    def isToeplitzMatrix(self, matrix):

        """

        :type matrix: List[List[int]]

        :rtype: bool

        """

        m = len(matrix)

        n = len(matrix[0])

        for i in range(m - 1):

            for j in range(n - 1):

                if matrix[i][j] != matrix[i+1][j+1]:

                    return False

        return True