题目要求：

输入参数：参数A，含有任意个数的?的数值字符串，如：12?4，?代表一位任意数

                    参数B，不含?的数值字符串，长度与参数A一致

输出结果：参数A比参数B大的可能数值个数

输入样例

36?1?8

236428

8?3

910

?

5



输出样例

100

0

4

#define num_max_length 20

int main(void)

{

	char num1[num_max_length];

	char num2[num_max_length];

	int result_temp=0, result=0;

	int num_length=0, num_index=0;

	int flag=0;

	while(1){

		memset(num1, 0, num_max_length);

		memset(num2, 0, num_max_length);

		result_temp=0;

		result = 0;

		flag = 0;

		printf("参数A:");

		fgets(num1, num_max_length, stdin);

		if(memcmp(num1, "end", 3)==0) break;

		printf("参数B:");

		fgets(num2, num_max_length, stdin);

		if(memcmp(num2, "end", 3)==0) break;

		if((num_length=strlen(num1))!=strlen(num2)){

			printf("num1 num2 length not match\n");

			break;

		}

		for(num_index=0; num_index<num_length; num_index++){

			if(num1[num_index]=='?'){

				if(flag == 0)

					result_temp = (int)('9'-num2[num_index])+result_temp*10;

				else

					result_temp = result_temp*10;

			}

			else{

				if(num1[num_index]==num2[num_index]){

					continue;

				}

				else if(num1[num_index]<num2[num_index]){

					//break;

					if(flag == 0){

						flag = 1;

					}

				}

				else{

					if(flag == 0){

						flag = 1;

						result_temp += 1;

					}

				}

			}

		}

		printf("参数A比参数B大有%d种可能\n", result_temp);

	}

	printf("用户终止程序\n");

	system("pause");

	return 0;

}