面向对象风格的单链表排序


//面对对象风格的单链表排序.

//
现在的主要问题是,排序的列表中不能出现0,原因是与NULL冲突. #include <iostream> using namespace std; const long int MAX = 2147483647; //长整形的最大值,即 (2^31)-1,在当前编译器中,int和long int都是4字节32位 typedef class LNode//重命名struct LNode为LNode { private: long int data; LNode *next;//在结构体中可以直接使用新名字LNode public: void CreateLinklist(LNode*& head); void printLinklist(LNode* p); void CopyLinklist(LNode*& head, LNode* b); void sort(LNode*& headA, LNode* p); }LNode; void LNode::CreateLinklist(LNode*& head) { cout << "请输入数字创建链表,以9999结束。\n"; head = new LNode; head->next = nullptr; LNode* flag; flag = head; long int t; cin >> t; while (t != 9999) { flag->data = t; flag->next = new LNode; //new会返回一个地址 flag = flag->next; cin >> t; } flag->next = nullptr; flag = head; } void LNode::printLinklist(LNode *p) { if (p->data == NULL) cout << "链表为空。\n"; else { cout << "链表的结构为:\n"; while (p->next != nullptr) { cout << p->data; p = p->next; if (p->next != nullptr) cout << " -> "; } } } void LNode::CopyLinklist(LNode *&head, LNode *b) { head = new LNode; head->next = nullptr; LNode* flag; flag = head; while (b->next != nullptr) { flag->data = b->data; flag->next = new LNode; flag = flag->next; b = b->next; } flag->next = nullptr; flag = head; } void LNode::sort(LNode *&headA, LNode *p) { LNode* copy; copy->CopyLinklist(copy, p); headA = new LNode; headA->next = nullptr; LNode* flagA; LNode* flagB; LNode* flagC; flagA = headA; flagB = copy; flagC = copy; long int g; int num = 0; while (copy->next != nullptr) { copy = copy->next; num++; } cout<<"该排序链表共有"<<num<<"个结点。\n"; copy = flagB; g = copy->data; if (num == 0) cout << "该排序链表为空!"; else { while (num > 0) { while (copy->next != nullptr) { if (g > copy->data && copy->data != NULL) { g = copy->data; flagC = copy; } copy = copy->next; } flagC->data = MAX; //将当前最小值设为一个原链表绝对不可能达到的极大值 flagA->data = g; flagA->next = new LNode; flagA = flagA->next; flagA->next = nullptr; copy = flagB; g = MAX; num--; } flagA = headA; } } int main() { LNode* LA; LA->CreateLinklist(LA); printf("\n"); LA->printLinklist(LA); printf("\n"); printf("\n"); LNode* LB; LB->sort(LB, LA); printf("\n"); LB->printLinklist(LB); return 0; }

 

面向对象风格的单链表排序

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