参考文章:对golang的Channel初始化的有缓存与无缓存解释 - Go语言中文网 - Golang中文社区

这篇文章没看懂，简单说下就是channel初始化的时候，make了缓存长度的话，就是带缓存的，没有make长度，就是不带缓存的。带缓存的只要缓存没有满，往channel里面写东西和从channel里面读东西就都是异步的，不会被阻塞的。但是如果是不带缓存的，必须是发送的东西有人收到后才能继续下一次发送；或者是接受的东西必须收到后才能继续下一次的接受。

func main() {
	jobs := make(chan int, 1)
	done := make(chan bool)
	go func() {
		//fmt.Println("GoStart")
		for i := 1; ; i++ {
			//fmt.Println("GoforSTART", i)
			j, more := <-jobs
			if more {
				fmt.Println("received job", j)
			} else {
				fmt.Println("received all jobs")
				done <- true
				return
			}
			//fmt.Println("GoforEND", i)
		}
	}()
	for j := 1; j <= 3; j++ {
		//fmt.Println("OutFOR", j)
		jobs <- j
		fmt.Println("sent job", j)
	}

	close(jobs)
	fmt.Println("sent all jobs")

	<-done
}

以参考的文章里面的程序举例，如上图，当有缓存的时候，执行结果如下(每次结果不一样)，只有当缓存满的时候才会被阻塞：

sent job 1
sent job 2
received job 1
received job 2
received job 3
sent job 3
sent all jobs
received all jobs
 

或者

received job 1
sent job 1
sent job 2
sent job 3
sent all jobs
received job 2
received job 3
received all jobs

当没有缓存时，执行结果如下（每次结果不一样）:

received job 1
sent job 1
sent job 2
received job 2
received job 3
sent job 3
sent all jobs
received all jobs
 

或者 

sent job 1
received job 1
received job 2
sent job 2
sent job 3
sent all jobs
received job 3
received all jobs
 

或者