我有两个名为Buyer和Car的模型,以及一个名为custom_row的自定义布局来显示ListView的行.

public class CustomAdapter extends BaseAdapter {
    Context c;
    ArrayList<Buyer> buyers;

    public CustomAdapter(Context c, ArrayList<Buyer> buyers) {
        this.c = c;
        this.buyers = buyers;
    }

    @Override
    public int getCount() {
        return buyers.size();
    }

    @Override
    public Object getItem(int position) {
        return buyers.get(position);
    }

    @Override
    public long getItemId(int position) {
        return position;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        if (convertView == null) {
            convertView = LayoutInflater.from(c).inflate(R.layout.custom_row, parent, false);
        }

        TextView tvBuyerName = (TextView) convertView.findViewById(R.id.tvBuyerName);
        TextView tvCarModel = (TextView) convertView.findViewById(R.id.tvCarModel);

        final Buyer b = (Buyer) this.getItem(position);

        tvBuyerName.setText(b.getBuyerName());

        return convertView;
    }
}

到目前为止,我只完成了上面的代码,而且我只能显示买家的名字.如何在ArrayList中创建另一个引用来建模Car,这样我就可以在同一个ListView中获取和显示来自模型买家和模型Car的信息？

解决方法:

一种方法是创建一个包含Car& Car的模型.买方数据.
由此你可以从同一个arraylist访问汽车和买家.

另一个是将两个arraylist(carList& buyerList)传递给适配器的构造函数.

ArrayList<Buyer> buyers;
ArrayList<Car> cars;

    public CustomAdapter(Context c, ArrayList<Buyer> buyers, ArrayList<Car> cars) {
        this.c = c;
        this.buyers = buyers;
        this.cars= cars;
    }

然后

final Buyer b = (Buyer) buyers.getItem(position);
tvBuyerName.setText(b.getBuyerName());

final Car c = (Car) cars.getItem(position);
tvCar.setText(c.getCarName());