Windowsphone 之xml序列化和反序列化的应用(WebService解析返回的数据DataSet )

关于Xml的序列化和反序列化:

可以看这篇文章,http://www.cnblogs.com/Windows-phone/p/3243575.html

WebService解析返回的数据DataSet

  <?xml version="1.0" encoding="utf-8" ?>
- <DataSet xmlns="http://WebXml.com.cn/">
-   <xs:schema id="getRegion" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
-     <xs:element name="getRegion" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
-       <xs:complexType>
-         <xs:choice minOccurs="0" maxOccurs="unbounded">
-           <xs:element name="Province">
-             <xs:complexType>
-               <xs:sequence>
                  <xs:element name="RegionID" type="xs:string" minOccurs="0" />
                  <xs:element name="RegionName" type="xs:string" minOccurs="0" />
                </xs:sequence>
              </xs:complexType>
            </xs:element>
-           <xs:element name="Country">
-             <xs:complexType>
-               <xs:sequence>
                  <xs:element name="RegionID" type="xs:string" minOccurs="0" />
                  <xs:element name="RegionName" type="xs:string" minOccurs="0" />
                </xs:sequence>
              </xs:complexType>
            </xs:element>
          </xs:choice>
        </xs:complexType>
      </xs:element>
    </xs:schema>
- <diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
-   <getRegion xmlns="">
-     <Province diffgr:id="Province1" msdata:rowOrder="0">
        <RegionID>3113</RegionID>
        <RegionName>黑龙江</RegionName>
      </Province>
-     <Province diffgr:id="Province2" msdata:rowOrder="1">
        <RegionID>3114</RegionID>
        <RegionName>吉林</RegionName>
      </Province>
-     <Province diffgr:id="Province3" msdata:rowOrder="2">
        <RegionID>3115</RegionID>
        <RegionName>辽宁</RegionName>
      </Province>      <Province diffgr:id="Province4" msdata:rowOrder="3">
        <RegionID>3116</RegionID>
        <RegionName>内蒙古</RegionName>
      </Province>
-     <Province diffgr:id="Province5" msdata:rowOrder="4">
        <RegionID>3117</RegionID>
        <RegionName>河北</RegionName>
      </Province>
-     <Province diffgr:id="Province6" msdata:rowOrder="5">
        <RegionID>3118</RegionID>
        <RegionName>河南</RegionName>
      </Province>
-     <Province diffgr:id="Province7" msdata:rowOrder="6">
        <RegionID>3119</RegionID>
        <RegionName>山东</RegionName>
      </Province>
-     .......  </getRegion>... 

在我们获取了这个Xml数据之后,我们如何解析这段数据,并将该数据转换成Province集合呢?
代码如下:

 static string head = "<?xml version=\"1.0\" encoding=\"utf-8\"?><Province>";
        //static string tail = "</{0}>";
        static string tail = "</Province>";
/// <summary>
        /// 获取多个实体对象
        /// </summary>
        /// <typeparam name="T">实体类型</typeparam>
        /// <param name="aoxe"></param>
        /// <returns></returns>
        public static ObservableCollection<T> GetAllEntitiesForDataSetXml<T>(ArrayOfXElement aoxe)
        {
            ObservableCollection<T> listT = new ObservableCollection<T>();
            XmlSerializer serializer = new XmlSerializer(typeof(T));
            T t = default(T);
            try
            {
                ].LastNode));//取出第二个结点中的内容
                StringBuilder sb = new StringBuilder();                                                                                                                

                foreach (var item in content.Nodes())
                {
                    //sb.Append(string.Format(head, typeof(T).Name));
                    sb.Append(head);
                    foreach (var obj in ((XElement)item).Nodes())
                    {

                        sb.Append(obj.ToString());
                    }
                    //sb.Append(string.Format(tail, typeof(T).Name));
                    sb.Append(tail);
                    string ss = sb.ToString();

                    StringReader sr = new StringReader(ss);

                    //反序列化,并将反序列化结果值赋给变量i
                    t = (T)serializer.Deserialize(sr);

                    listT.Add(t);
                    sr.Close();
                    sr.Dispose();
                    sb.Clear();
                }
            }
            catch
            {

            }
            return listT;
        }
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